Sistem Persamaan Linear

Contoh Soal

3x3 + 5x1 = 7
2x2 + 3x3 = 9
4x2 = 11

a. Ubahlah sistem persamaan linear tersebut menjadi matriks A . x = B
b. Carilah x1, x2 dan x3 menggunakan metode Invers, metode Crammer, metode Gauss, dan metode Gauss-Jordan !

Jawaban :
a.
   
           A                                                                          x                                                           B
b.
  • Metode Invers
A-1 = adj A  x B
             det A
                 =  -12     12     -6             7
                       0       0      -15     x     9
                       0     -20      10           11
                                   -60
                 =  -84 + 108     + (-66)
                       0   +   0       + (-165)
                       0   + (-180) + 110
                                -60
                 =  -42                    -42 / -60
                     -165      atau      -165 / -60
                     -70                     -70 / -60

                     -60

          x1       7 / 10
          x2   =  11 / 4
          x3       7 / 6

  • Metode Crammer
det A =
5   0
0   2   

0   4

                
                
                   = (5 x 2 x 0) + (0 x 3 x 0) + (3 x 0 x 4) - (3 x 2 x 0) - (5 x 3 x 4) - (0 x 0 x 0)
                   = 0 + 0 + 0 - 0 - 60 - 0
                   = -60
det x1 =
7    0
9    2

11   4

                
                 
                    = (7 x 2 x 0) + (0 x 3 11) + (3 x 9 x 4) - (3 x 2 x 11) - (7 x 3 x 4) - (0 x 9 x 0)
                    = 0 + 0 + 108 - 66 - 84 - 0
                    = -42
det x2 =
5   7
0   9

0   11

               
                 
                    = (5 x 9 x 0) + (7 x 3 x 0) + (3 x 0 x 11) - (3 x 9 x 0) - (5 x 3 x 11) - (7 x 0 x 0)
                    = 0 + 0 + 0 - 0 - 165 - 0
                    = -165
det x3 =
5   0
 0   2

 0   4

               
               
                    = (5 x 2 x 11) + (0 x 9 x 0) + (7 x 0 x 4) - (7 x 2 x 0) - (5 x 9 x 4) - (0 x 0 x 11)
                    = 110 + 0 + 0 - 0 - 180 - 0
                    = -70
Solusi x1 = det x1
                  det A
               = -42 / -60
               = 7 / 10

          x2 = det x2
                  det A
               = -165 / -60
               = 11 / 4

          x3 = det x3
                  det A
               = -70 / -60
               = 7 / 6

  •  Metode Gauss
                       H1 (1/5)





H2 (1/2)                                    H32 (-4)

H3 (-1/2)

Persamaan 3 = x3 = 7 / 6

Persamaan 2 = x2 + 3 / 2 (x3) = 9 / 2
                        x2 + 3 / 2 (7 / 6) = 9 / 2
                        x2 + 21 / 12 = 9 / 2
                        x2 = 9 / 2 - 21 / 12
                        x2 = 54 - 21
                                   12
                        x2 = 33 / 12
                        x2 = 11 / 4

Persamaan 1 = x1 + 0 (x2) + 3 / 5 (x3) = 7 / 5
                        x1 + 0 (11 / 4) + 3 / 5 (7 / 6) = 7 / 5
                        x1 + 0 + 21 / 30 = 7 / 5
                        x1 = 7 / 5 - 21 / 30
                        x1 = 42 - 21
                                    30
                        x1 = 21 / 30
                        x1 = 7 / 10

  • Metode Gauss-Jordan

                    H1 (1/5)
     





H2 (1/2)                                          H32 (-4)

H3 (-1/2)                                   H13 (-3/5)

H23 (-3/2)

                            











Persamaan 3 = x3 = 7 / 6
Persamaan 2 = x2 = 11 / 4
Persamaan 1 = x1 = 7 / 10

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